Sample recipe
10#'s Pale malt 27 GU's per pound per gallon at 75% effeciency
2 #'s Cane Sugar 46 GU's per pound per gallon at 100% effeciency
=
270 GU's from the Pale, 92 from the sugar for a total of 383 GU's.
382/5gal = 76.4GU's = 1.076
Lets say the beer finished at 1.010. The simple sugar is 100% fermentable... with it in the equation thats about 86% Apparent Attenuation.
My logic is to remove the simple sugar from the equation... and just measure the rest, to find the real apparent attenuation for the yeast strain.
92/5gal = 18.4GU's = 1.018 GU's from Simple sugar.
1.076 -0.018 = 1.058
Then I would use that for the apparent attenuation calculation... 48 GU's/58GU's for an apparent attenuation of 82%.
Is it safe to assume that the apparent attenuation I got would be 82% in this scenario? My only issue with this, is that the Specific Gravity of the Alcohol produced by the simple sugar is less than 1.000 bringing the FG down artificially even when it factored out. Meaning... w/o the sugar, maybe the recipe would give 1.058 and finish at 1.012 instead.
Am I making any sense, or am I just being a little too anal? Thanks for any responses, or if anyone knows the correct/proper way to calculate this, I'd be greatful!



